In the given half-reaction Cr_2O_7^{2-} + ZH^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To balance the half-reaction $Cr_2O_7^{2-} + ZH^{+} + e^- 	o Cr^{3+} + H_2O$:$1$. Balance the $Cr$ atoms: $Cr_2O_7^{2-} + ZH^{+} + e^- 	o 2Cr^{3

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(D) To balance the half-reaction $Cr_2O_7^{2-} + ZH^{+} + e^- 	o Cr^{3+} + H_2O$:$1$. Balance the $Cr$ atoms: $Cr_2O_7^{2-} + ZH^{+} + e^- 	o 2Cr^{3+} + H_2O$.$2$. Balance the $O$ atoms by adding $H_2O$: $Cr_2O_7^{2-} + ZH^{+} + e^- 	o 2Cr^{3+} + 7H_2O$.$3$. Balance the $H$ atoms: There are $14$ hydrogen atoms on the right side,so $Z = 14$.$4$. Balance the charge: The left side has $-2 + 14 = +12$ charge (assuming $6$ electrons are added). The right side has $2 	imes (+3) = +6$. To balance,we need $6$ electrons: $Cr_2O_7^{2-} + 14H^{+} + 6e^- 	o 2Cr^{3+} + 7H_2O$. Thus,$Z = 14$.

In the given half-reaction $Cr_2O_7^{2-} + ZH^{+} + e^- \to Cr^{3+} + H_2O$,find the value of $Z$.

Similar Questions

Which of the following reagents causes the aqueous colored solution of acidic $KMnO_4$ to become colorless?

Molecular weight of $Cu_2S$ is $M$. In the following reaction its equivalent weight is $M / x$. What is $x$?
$Cu_2S + MnO_4^{-} \rightarrow Cu^{2+} + Mn^{2+} + SO_2$

One of the products formed due to the reaction between $KMnO_4$ and $HCl$ is

The equivalent weight of ${S_2O_3^{2-}}$ in the reaction where it acts as a reductant is ...... . ${2S_2O_3^{2-} + I_2 \rightarrow S_4O_6^{2-} + 2I^-}$

In the half-reaction $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$,the equivalent weight of $Cr_2O_7^{2-}$ is obtained by dividing its molecular weight by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module